5n^2=78

Solution for 5n^2=78 equation:

5n^2=78

We move all terms to the left:

5n^2-(78)=0

a = 5; b = 0; c = -78;
Δ = b2-4ac
Δ = 02-4·5·(-78)
Δ = 1560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1560}=\sqrt{4*390}=\sqrt{4}*\sqrt{390}=2\sqrt{390}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{390}}{2*5}=\frac{0-2\sqrt{390}}{10}
=-\frac{2\sqrt{390}}{10}
=-\frac{\sqrt{390}}{5}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{390}}{2*5}=\frac{0+2\sqrt{390}}{10}
=\frac{2\sqrt{390}}{10}
=\frac{\sqrt{390}}{5}
$